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Showing posts with label 4. Show all posts
Showing posts with label 4. Show all posts
Tuesday, 11 June 2013
Saturday, 8 June 2013
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as R = {(a, b) : b = a + 1} is reflexive, symmetric or transitive.
Answer
Method -1
Let A = {1, 2, 3, 4, 5, 6}.
A relation R is defined on set A as: R = {(a, b):
b = a + 1}
∴R
= {(1, 2), (2, 3), (3, 4), (4, 5), (5, 6)} We can find (a, a) ∉ R, where a ∈ A.
For instance,
(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6) ∉ R
∴R
is not reflexive.
It can be observed that (1, 2) ∈ R, but (2, 1) ∉ R.
∴R
is not symmetric. Now, (1, 2), (2, 3) ∈
R
But,
(1, 3) ∉
R
∴R
is not transitive
Hence, R is neither reflexive, nor symmetric, nor
transitive.
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Method- 2
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Do you know any other method of solving of this question ?
3. Check whether the relation R defined in the set {1, 2, 3, 4, 5,
6} as R = {(a, b) : b = a + 1} is reflexive,
symmetric or transitive.
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