Check which of the following are solutions of the equation x − 2y = 4 and which are not

Question 3: Check which of the following are solutions of the equation x − 2y = 4 and which are not: (i) (0, 2 (ii) (2, 0) (iii) (4, 0) (iv) (v) (1, 1)

Answer:

(i) (0, 2)

Putting x = 0 and y = 2 in the L.H.S of the given equation,
x − 2y = 0 − 2×2 = − 4 ≠ 4
L.H.S ≠ R.H.S
Therefore, (0, 2) is not a solution of this equation.

(ii) (2, 0)

Putting x = 2 and y = 0 in the L.H.S of the given equation,
x − 2y = 2 − 2 × 0 = 2 ≠ 4
L.H.S ≠ R.H.S
Therefore, (2, 0) is not a solution of this equation.

(iii) (4, 0)

Putting x = 4 and y = 0 in the L.H.S of the given equation,
x − 2y = 4 − 2(0)
= 4 = R.H.S
Therefore, (4, 0) is a solution of this equation.

(iv)

(v) (1, 1)

Putting x = 1 and y = 1 in the L.H.S of the given equation,
x − 2y = 1 − 2(1) = 1 − 2 = − 1 ≠ 4
L.H.S ≠ R.H.S
Therefore, (1, 1) is not a solution of this equation.