Question
1.20: A point charge causes
an electric flux of −1.0 × 103 Nm2/C to pass through a
spherical Gaussian surface of 10.0 cm radius centered on the charge. (a) If the
radius of the Gaussian surface were doubled, how much flux would pass through
the surface? (b) What is the value of the point charge?
Answer:
Method - 1
Electric flux, Φ = −1.0
× 103 N m2/C Radius of the Gaussian surface,
r = 10.0 cm
Electric flux piercing
out through a surface depends on the net charge enclosed inside a body. It does
not depend on the size of the body. If the radius of the Gaussian surface is
doubled, then the flux passing through the surface remains the same i.e., −103
N m2/C.
Electric flux is given
by the relation,
q = Net charge enclosed
by the spherical surface
∈0 = Permittivity of free space = 8.854 × 10−12
N−1C2 m−2
= −1.0 × 103
× 8.854 × 10−12
= −8.854 × 10−9
C
= −8.854 nC
Method - 2
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