Sunday 30 June 2013

The ratio of the sums of m and n terms of an A.P. is m2: n2. Show that the ratio of mth and nth term is (2m – 1): (2n – 1).

The ratio of the sums of m and n terms of an A.P. is m2: n2. Show that the ratio of mth
and nth term is (2m – 1): (2n – 1).
Answer
Let a and b be the first term and the common difference of the A.P. respectively.
According to the given condition,
.





1 comment:

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