Two large, thin metal plates are parallel and close
to each other. On their inner faces, the plates have surface charge densities
of opposite signs and of magnitude 17.0 × 10−22 C/m2. What is E: (a) in the outer region of the first
plate, (b) in the outer region of the second plate, and (c) between the plates?
Answer:
Method - 1
The
situation is represented in the following figure.
A and B are
two parallel plates close to each other. Outer region of plate A is labelled as I, outer region of plate B is labelled as III, and the region between the plates, A and B, is labelled as II.
Charge density of
plate A, σ = 17.0 × 10−22 C/m2 Charge density of
plate B, σ = −17.0 × 10−22 C/m2
In the regions, I and
III, electric field E is zero. This is because charge is not enclosed by the respective plates.
Electric field E in region II is given by the
relation,
Where,
∴0 = Permittivity of free
space = 8.854 × 10−12 N−1C2 m−2
= 1.92 × 10−10 N/C
Therefore, electric
field between the plates is 1.92 × 10−10 N/C.
Method - 2
Both the methods r same
ReplyDeleteI understood but the both methods are same there is no change......
ReplyDelete