Question 2.11: A 25 watt bulb emits monochromatic yellow light of wavelength of 0.57µm. Calculate the rate of emission of quanta per second.
Answer
Power of bulb, P = 25 Watt = 25 Js-1
Energy of one photon, E = hν
Substituting the values in the given expression of E:
E = 34.87 × 10-20 J
Rate of emission of quanta per second
Answer
Power of bulb, P = 25 Watt = 25 Js-1
Energy of one photon, E = hν
Substituting the values in the given expression of E:
E = 34.87 × 10-20 J
Rate of emission of quanta per second
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