Q- 2.59: If the velocity of the electron in Bohr’s first orbit is 2.19 × 106 ms-1, calculate the de Broglie wavelength associated with it.
Answer
According to de Broglie’s equation,
Where,
λ = wavelength associated with the electron
h = Planck’s constant
m = mass of electron
v = velocity of electron
Substituting the values in the expression of λ:
λ = 332 pm
Wavelength associated with the electron = 332 pm
Answer
According to de Broglie’s equation,
Where,
λ = wavelength associated with the electron
h = Planck’s constant
m = mass of electron
v = velocity of electron
Substituting the values in the expression of λ:
λ = 332 pm
Wavelength associated with the electron = 332 pm
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