Question 2.8: What is the number of photons of light with a wavelength of 4000 pm that provide 1 J of energy?

Answer

Energy (E) of a photon = hν

Energy (E

Where,

λ = wavelength of light = 4000 pm = 4000 ×10

c = velocity of light in vacuum = 3 × 10

h = Planck’s constant = 6.626 × 10

Substituting the values in the given expression of n:

Hence, the number of photons with a wavelength of 4000 pm and energy of 1 J are

2.012 × 10

Answer

Energy (E) of a photon = hν

Energy (E

_{n}) of ‘n’ photons = nhνWhere,

λ = wavelength of light = 4000 pm = 4000 ×10

^{-12}mc = velocity of light in vacuum = 3 × 10

^{8 }m/sh = Planck’s constant = 6.626 × 10

^{-34}JsSubstituting the values in the given expression of n:

Hence, the number of photons with a wavelength of 4000 pm and energy of 1 J are

2.012 × 10

^{16}.
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