Question 2.33: What transition in the hydrogen spectrum would have the same wavelength as the Balmer transition n = 4 to n = 2 of He+ spectrum?
Answer
Answer
For He+ ion, the wave number associated with the Balmer transition, n = 4 to n = 2
the wave number is given by:
Where,
n1 = 2
n2 = 4
Z = atomic number of helium
According to the question, the desired transition for hydrogen will have the same wavelength as that of He+.
By hit and trail method, the equality given by equation (1) is true only when
Where,
n1 = 2
n2 = 4
Z = atomic number of helium
According to the question, the desired transition for hydrogen will have the same wavelength as that of He+.
n1 = 1and n2 = 2.
∴ The transition for n2 = 2 to n = 1 in hydrogen spectrum would have the same wavelength as Balmer transition n = 4 to n = 2 of He+ spectrum.
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