Discuss the shape of the following molecules using the VSEPR model: BeCl2, BCl3, SiCl4, AsF5, H2S,
PH3
Answer
BeCl2
The central atom has no lone pair and there are two bond pairs. i.e., BeCl
2 is of the type AB
2. Hence, it has a linear shape.
BCl3
The central atom has no lone pair and there are three bond pairs. Hence, it is of the type AB
3. Hence, it is trigonal planar.
SiCl4
The central atom has no lone pair and there are four bond pairs. Hence, the shape of SiCl
4 is tetrahedral being the AB
4 type
molecule.
AsF5
The central atom has no lone pair and there are five bond pairs. Hence, AsF5 is of the type AB5. Therefore, the shape is trigonal
bipyramidal.
H2S
The central atom has one lone pair and there are two bond pairs. Hence, H
2S is of the type AB
2E. The shape is Bent.
PH3
The central atom has one lone pair and there are three bond pairs. Hence, PH
3 is of the AB
3E type. Therefore, the shape is trigonal
bipyramidal.
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